5(2y-1)=-7(y-1)+5

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Solution for 5(2y-1)=-7(y-1)+5 equation: 



5(2y-1)=-7(y-1)+5

We move all terms to the left:

5(2y-1)-(-7(y-1)+5)=0

We multiply parentheses

10y-(-7(y-1)+5)-5=0



We calculate terms in parentheses: -(-7(y-1)+5), so:

-7(y-1)+5

We multiply parentheses

-7y+7+5

We add all the numbers together, and all the variables

-7y+12

Back to the equation:

-(-7y+12)



We get rid of parentheses

10y+7y-12-5=0

We add all the numbers together, and all the variables

17y-17=0

We move all terms containing y to the left, all other terms to the right

17y=17

y=17/17

y=1

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