5(2y-1)=2(y-1)

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Solution for 5(2y-1)=2(y-1) equation: 



5(2y-1)=2(y-1)

We move all terms to the left:

5(2y-1)-(2(y-1))=0

We multiply parentheses

10y-(2(y-1))-5=0



We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)



We get rid of parentheses

10y-2y+2-5=0

We add all the numbers together, and all the variables

8y-3=0

We move all terms containing y to the left, all other terms to the right

8y=3

y=3/8

y=3/8

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