5(2y-2)=3y+11

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Solution for 5(2y-2)=3y+11 equation:



5(2y-2)=3y+11
We move all terms to the left:
5(2y-2)-(3y+11)=0
We multiply parentheses
10y-(3y+11)-10=0
We get rid of parentheses
10y-3y-11-10=0
We add all the numbers together, and all the variables
7y-21=0
We move all terms containing y to the left, all other terms to the right
7y=21
y=21/7
y=3

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