5(2y-2)=3y+11

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Solution for 5(2y-2)=3y+11 equation: 



5(2y-2)=3y+11

We move all terms to the left:

5(2y-2)-(3y+11)=0

We multiply parentheses

10y-(3y+11)-10=0

We get rid of parentheses

10y-3y-11-10=0

We add all the numbers together, and all the variables

7y-21=0

We move all terms containing y to the left, all other terms to the right

7y=21

y=21/7

y=3

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