5(2y-3)+4=6y-10

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Solution for 5(2y-3)+4=6y-10 equation: 



5(2y-3)+4=6y-10

We move all terms to the left:

5(2y-3)+4-(6y-10)=0

We multiply parentheses

10y-(6y-10)-15+4=0

We get rid of parentheses

10y-6y+10-15+4=0

We add all the numbers together, and all the variables

4y-1=0

We move all terms containing y to the left, all other terms to the right

4y=1

y=1/4

y=1/4

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