5(2y-3)/4-2(1+4y)/6=7/3

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Solution for 5(2y-3)/4-2(1+4y)/6=7/3 equation:


5(2y-3)/4-2(1+4y)/6=7/3

We simplify the equation to the form, which is simple to understand
5(2y-3)/4-2(1+4y)/6=7/3

Simplifying:
5*(2y-3)/4-2*(1+4y)/6=+2.33333333333

Reorder the terms in parentheses
+(+10y-15)/4-2*(1+4y)/6=+2.33333333333

Reorder the terms in parentheses
+(+2.5y-3.75)-2*(1+4y)/6=+2.33333333333

Remove unnecessary parentheses
+2.5y-3.75-2+*(+1+4y+)+/6=+2.33333333333

Reorder the terms in parentheses
+2.5y-3.75+(-2-8y)/6=+2.33333333333

Reorder the terms in parentheses
+2.5y-3.75+(-0.333333333333-1.33333333333y)=+2.33333333333

Remove unnecessary parentheses
+2.5y-3.75-0.333333333333-1.33333333333y=+2.33333333333

We move all terms containing y to the left and all other terms to the right.
+2.5y-1.33333333333y=+2.33333333333+3.75 + 0.333333333333

We simplify left and right side of the equation.
+1.16666666667y=+6.41666666667

We divide both sides of the equation by 1.16666666667 to get y.
y=5.49999999998

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