5(2y-3)=-2(5-2y)

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Solution for 5(2y-3)=-2(5-2y) equation: 



5(2y-3)=-2(5-2y)

We move all terms to the left:

5(2y-3)-(-2(5-2y))=0

We add all the numbers together, and all the variables

5(2y-3)-(-2(-2y+5))=0

We multiply parentheses

10y-(-2(-2y+5))-15=0



We calculate terms in parentheses: -(-2(-2y+5)), so:

-2(-2y+5)

We multiply parentheses

4y-10

Back to the equation:

-(4y-10)



We get rid of parentheses

10y-4y+10-15=0

We add all the numbers together, and all the variables

6y-5=0

We move all terms containing y to the left, all other terms to the right

6y=5

y=5/6

y=5/6

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