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5(2y-3)=3(2y+4)
We move all terms to the left:
5(2y-3)-(3(2y+4))=0
We multiply parentheses
10y-(3(2y+4))-15=0
We calculate terms in parentheses: -(3(2y+4)), so:We get rid of parentheses
3(2y+4)
We multiply parentheses
6y+12
Back to the equation:
-(6y+12)
10y-6y-12-15=0
We add all the numbers together, and all the variables
4y-27=0
We move all terms containing y to the left, all other terms to the right
4y=27
y=27/4
y=6+3/4
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