5(2y-3)=9(y+3)-42

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Solution for 5(2y-3)=9(y+3)-42 equation: 



5(2y-3)=9(y+3)-42

We move all terms to the left:

5(2y-3)-(9(y+3)-42)=0

We multiply parentheses

10y-(9(y+3)-42)-15=0



We calculate terms in parentheses: -(9(y+3)-42), so:

9(y+3)-42

We multiply parentheses

9y+27-42

We add all the numbers together, and all the variables

9y-15

Back to the equation:

-(9y-15)



We get rid of parentheses

10y-9y+15-15=0

We add all the numbers together, and all the variables

y=0

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