5(2y-4)=5(3y+1)

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Solution for 5(2y-4)=5(3y+1) equation: 



5(2y-4)=5(3y+1)

We move all terms to the left:

5(2y-4)-(5(3y+1))=0

We multiply parentheses

10y-(5(3y+1))-20=0



We calculate terms in parentheses: -(5(3y+1)), so:

5(3y+1)

We multiply parentheses

15y+5

Back to the equation:

-(15y+5)



We get rid of parentheses

10y-15y-5-20=0

We add all the numbers together, and all the variables

-5y-25=0

We move all terms containing y to the left, all other terms to the right

-5y=25

y=25/-5

y=-5

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