5(2y-7)-4y=6(y-5)-3

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Solution for 5(2y-7)-4y=6(y-5)-3 equation: 



5(2y-7)-4y=6(y-5)-3

We move all terms to the left:

5(2y-7)-4y-(6(y-5)-3)=0

We add all the numbers together, and all the variables

-4y+5(2y-7)-(6(y-5)-3)=0

We multiply parentheses

-4y+10y-(6(y-5)-3)-35=0



We calculate terms in parentheses: -(6(y-5)-3), so:

6(y-5)-3

We multiply parentheses

6y-30-3

We add all the numbers together, and all the variables

6y-33

Back to the equation:

-(6y-33)



We add all the numbers together, and all the variables

6y-(6y-33)-35=0

We get rid of parentheses

6y-6y+33-35=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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