5(2z+1)=4z+11

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Solution for 5(2z+1)=4z+11 equation:


Simplifying
5(2z + 1) = 4z + 11

Reorder the terms:
5(1 + 2z) = 4z + 11
(1 * 5 + 2z * 5) = 4z + 11
(5 + 10z) = 4z + 11

Reorder the terms:
5 + 10z = 11 + 4z

Solving
5 + 10z = 11 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
5 + 10z + -4z = 11 + 4z + -4z

Combine like terms: 10z + -4z = 6z
5 + 6z = 11 + 4z + -4z

Combine like terms: 4z + -4z = 0
5 + 6z = 11 + 0
5 + 6z = 11

Add '-5' to each side of the equation.
5 + -5 + 6z = 11 + -5

Combine like terms: 5 + -5 = 0
0 + 6z = 11 + -5
6z = 11 + -5

Combine like terms: 11 + -5 = 6
6z = 6

Divide each side by '6'.
z = 1

Simplifying
z = 1

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