5(2z+3)(3z+4)=15z(2z+7)

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Solution for 5(2z+3)(3z+4)=15z(2z+7) equation: 



5(2z+3)(3z+4)=15z(2z+7)

We move all terms to the left:

5(2z+3)(3z+4)-(15z(2z+7))=0

We multiply parentheses ..

5(+6z^2+8z+9z+12)-(15z(2z+7))=0



We calculate terms in parentheses: -(15z(2z+7)), so:

15z(2z+7)

We multiply parentheses

30z^2+105z

Back to the equation:

-(30z^2+105z)



We multiply parentheses

30z^2+40z+45z-(30z^2+105z)+60=0

We get rid of parentheses

30z^2-30z^2+40z+45z-105z+60=0

We add all the numbers together, and all the variables

-20z+60=0

We move all terms containing z to the left, all other terms to the right

-20z=-60

z=-60/-20

z=+3

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