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5(2z+5)=5(z+2)
We move all terms to the left:
5(2z+5)-(5(z+2))=0
We multiply parentheses
10z-(5(z+2))+25=0
We calculate terms in parentheses: -(5(z+2)), so:We get rid of parentheses
5(z+2)
We multiply parentheses
5z+10
Back to the equation:
-(5z+10)
10z-5z-10+25=0
We add all the numbers together, and all the variables
5z+15=0
We move all terms containing z to the left, all other terms to the right
5z=-15
z=-15/5
z=-3
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