5(2z+5)=5(z+2)

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Solution for 5(2z+5)=5(z+2) equation: 



5(2z+5)=5(z+2)

We move all terms to the left:

5(2z+5)-(5(z+2))=0

We multiply parentheses

10z-(5(z+2))+25=0



We calculate terms in parentheses: -(5(z+2)), so:

5(z+2)

We multiply parentheses

5z+10

Back to the equation:

-(5z+10)



We get rid of parentheses

10z-5z-10+25=0

We add all the numbers together, and all the variables

5z+15=0

We move all terms containing z to the left, all other terms to the right

5z=-15

z=-15/5

z=-3

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