5(2z-1)+7=7z-4(z+3)

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Solution for 5(2z-1)+7=7z-4(z+3) equation:


Simplifying
5(2z + -1) + 7 = 7z + -4(z + 3)

Reorder the terms:
5(-1 + 2z) + 7 = 7z + -4(z + 3)
(-1 * 5 + 2z * 5) + 7 = 7z + -4(z + 3)
(-5 + 10z) + 7 = 7z + -4(z + 3)

Reorder the terms:
-5 + 7 + 10z = 7z + -4(z + 3)

Combine like terms: -5 + 7 = 2
2 + 10z = 7z + -4(z + 3)

Reorder the terms:
2 + 10z = 7z + -4(3 + z)
2 + 10z = 7z + (3 * -4 + z * -4)
2 + 10z = 7z + (-12 + -4z)

Reorder the terms:
2 + 10z = -12 + 7z + -4z

Combine like terms: 7z + -4z = 3z
2 + 10z = -12 + 3z

Solving
2 + 10z = -12 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
2 + 10z + -3z = -12 + 3z + -3z

Combine like terms: 10z + -3z = 7z
2 + 7z = -12 + 3z + -3z

Combine like terms: 3z + -3z = 0
2 + 7z = -12 + 0
2 + 7z = -12

Add '-2' to each side of the equation.
2 + -2 + 7z = -12 + -2

Combine like terms: 2 + -2 = 0
0 + 7z = -12 + -2
7z = -12 + -2

Combine like terms: -12 + -2 = -14
7z = -14

Divide each side by '7'.
z = -2

Simplifying
z = -2

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