5(2z-1)-2(z-2)=2(z+1)

Solution for 5(2z-1)-2(z-2)=2(z+1) equation:

Simplifying
5(2z + -1) + -2(z + -2) = 2(z + 1)

Reorder the terms:
5(-1 + 2z) + -2(z + -2) = 2(z + 1)
(-1 * 5 + 2z * 5) + -2(z + -2) = 2(z + 1)
(-5 + 10z) + -2(z + -2) = 2(z + 1)

Reorder the terms:
-5 + 10z + -2(-2 + z) = 2(z + 1)
-5 + 10z + (-2 * -2 + z * -2) = 2(z + 1)
-5 + 10z + (4 + -2z) = 2(z + 1)

Reorder the terms:
-5 + 4 + 10z + -2z = 2(z + 1)

Combine like terms: -5 + 4 = -1
-1 + 10z + -2z = 2(z + 1)

Combine like terms: 10z + -2z = 8z
-1 + 8z = 2(z + 1)

Reorder the terms:
-1 + 8z = 2(1 + z)
-1 + 8z = (1 * 2 + z * 2)
-1 + 8z = (2 + 2z)

Solving
-1 + 8z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-1 + 8z + -2z = 2 + 2z + -2z

Combine like terms: 8z + -2z = 6z
-1 + 6z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-1 + 6z = 2 + 0
-1 + 6z = 2

Add '1' to each side of the equation.
-1 + 1 + 6z = 2 + 1

Combine like terms: -1 + 1 = 0
0 + 6z = 2 + 1
6z = 2 + 1

Combine like terms: 2 + 1 = 3
6z = 3

Divide each side by '6'.
z = 0.5

Simplifying
z = 0.5