5(2z-1)-2(z-7)=41

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Solution for 5(2z-1)-2(z-7)=41 equation:


Simplifying
5(2z + -1) + -2(z + -7) = 41

Reorder the terms:
5(-1 + 2z) + -2(z + -7) = 41
(-1 * 5 + 2z * 5) + -2(z + -7) = 41
(-5 + 10z) + -2(z + -7) = 41

Reorder the terms:
-5 + 10z + -2(-7 + z) = 41
-5 + 10z + (-7 * -2 + z * -2) = 41
-5 + 10z + (14 + -2z) = 41

Reorder the terms:
-5 + 14 + 10z + -2z = 41

Combine like terms: -5 + 14 = 9
9 + 10z + -2z = 41

Combine like terms: 10z + -2z = 8z
9 + 8z = 41

Solving
9 + 8z = 41

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 8z = 41 + -9

Combine like terms: 9 + -9 = 0
0 + 8z = 41 + -9
8z = 41 + -9

Combine like terms: 41 + -9 = 32
8z = 32

Divide each side by '8'.
z = 4

Simplifying
z = 4

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