5(2z-1)-4(z+3)=4(z+1)

Solution for 5(2z-1)-4(z+3)=4(z+1) equation:

Simplifying
5(2z + -1) + -4(z + 3) = 4(z + 1)

Reorder the terms:
5(-1 + 2z) + -4(z + 3) = 4(z + 1)
(-1 * 5 + 2z * 5) + -4(z + 3) = 4(z + 1)
(-5 + 10z) + -4(z + 3) = 4(z + 1)

Reorder the terms:
-5 + 10z + -4(3 + z) = 4(z + 1)
-5 + 10z + (3 * -4 + z * -4) = 4(z + 1)
-5 + 10z + (-12 + -4z) = 4(z + 1)

Reorder the terms:
-5 + -12 + 10z + -4z = 4(z + 1)

Combine like terms: -5 + -12 = -17
-17 + 10z + -4z = 4(z + 1)

Combine like terms: 10z + -4z = 6z
-17 + 6z = 4(z + 1)

Reorder the terms:
-17 + 6z = 4(1 + z)
-17 + 6z = (1 * 4 + z * 4)
-17 + 6z = (4 + 4z)

Solving
-17 + 6z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-17 + 6z + -4z = 4 + 4z + -4z

Combine like terms: 6z + -4z = 2z
-17 + 2z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-17 + 2z = 4 + 0
-17 + 2z = 4

Add '17' to each side of the equation.
-17 + 17 + 2z = 4 + 17

Combine like terms: -17 + 17 = 0
0 + 2z = 4 + 17
2z = 4 + 17

Combine like terms: 4 + 17 = 21
2z = 21

Divide each side by '2'.
z = 10.5

Simplifying
z = 10.5