5(2z-1)-5(z+2)=2(z+1)

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Solution for 5(2z-1)-5(z+2)=2(z+1) equation:


Simplifying
5(2z + -1) + -5(z + 2) = 2(z + 1)

Reorder the terms:
5(-1 + 2z) + -5(z + 2) = 2(z + 1)
(-1 * 5 + 2z * 5) + -5(z + 2) = 2(z + 1)
(-5 + 10z) + -5(z + 2) = 2(z + 1)

Reorder the terms:
-5 + 10z + -5(2 + z) = 2(z + 1)
-5 + 10z + (2 * -5 + z * -5) = 2(z + 1)
-5 + 10z + (-10 + -5z) = 2(z + 1)

Reorder the terms:
-5 + -10 + 10z + -5z = 2(z + 1)

Combine like terms: -5 + -10 = -15
-15 + 10z + -5z = 2(z + 1)

Combine like terms: 10z + -5z = 5z
-15 + 5z = 2(z + 1)

Reorder the terms:
-15 + 5z = 2(1 + z)
-15 + 5z = (1 * 2 + z * 2)
-15 + 5z = (2 + 2z)

Solving
-15 + 5z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-15 + 5z + -2z = 2 + 2z + -2z

Combine like terms: 5z + -2z = 3z
-15 + 3z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-15 + 3z = 2 + 0
-15 + 3z = 2

Add '15' to each side of the equation.
-15 + 15 + 3z = 2 + 15

Combine like terms: -15 + 15 = 0
0 + 3z = 2 + 15
3z = 2 + 15

Combine like terms: 2 + 15 = 17
3z = 17

Divide each side by '3'.
z = 5.666666667

Simplifying
z = 5.666666667

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