5(2z-1)=(3z-21)

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Solution for 5(2z-1)=(3z-21) equation: 



5(2z-1)=(3z-21)

We move all terms to the left:

5(2z-1)-((3z-21))=0

We multiply parentheses

10z-((3z-21))-5=0



We calculate terms in parentheses: -((3z-21)), so:

(3z-21)

We get rid of parentheses

3z-21

Back to the equation:

-(3z-21)



We get rid of parentheses

10z-3z+21-5=0

We add all the numbers together, and all the variables

7z+16=0

We move all terms containing z to the left, all other terms to the right

7z=-16

z=-16/7

z=-2+2/7

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