5(2z-1)=4(3z+4)

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Solution for 5(2z-1)=4(3z+4) equation: 



5(2z-1)=4(3z+4)

We move all terms to the left:

5(2z-1)-(4(3z+4))=0

We multiply parentheses

10z-(4(3z+4))-5=0



We calculate terms in parentheses: -(4(3z+4)), so:

4(3z+4)

We multiply parentheses

12z+16

Back to the equation:

-(12z+16)



We get rid of parentheses

10z-12z-16-5=0

We add all the numbers together, and all the variables

-2z-21=0

We move all terms containing z to the left, all other terms to the right

-2z=21

z=21/-2

z=-10+1/2

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