5(2z-2)=9(z-4)

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Solution for 5(2z-2)=9(z-4) equation: 



5(2z-2)=9(z-4)

We move all terms to the left:

5(2z-2)-(9(z-4))=0

We multiply parentheses

10z-(9(z-4))-10=0



We calculate terms in parentheses: -(9(z-4)), so:

9(z-4)

We multiply parentheses

9z-36

Back to the equation:

-(9z-36)



We get rid of parentheses

10z-9z+36-10=0

We add all the numbers together, and all the variables

z+26=0

We move all terms containing z to the left, all other terms to the right

z=-26

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