5(2z-3)=9(z+15)

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Solution for 5(2z-3)=9(z+15) equation: 



5(2z-3)=9(z+15)

We move all terms to the left:

5(2z-3)-(9(z+15))=0

We multiply parentheses

10z-(9(z+15))-15=0



We calculate terms in parentheses: -(9(z+15)), so:

9(z+15)

We multiply parentheses

9z+135

Back to the equation:

-(9z+135)



We get rid of parentheses

10z-9z-135-15=0

We add all the numbers together, and all the variables

z-150=0

We move all terms containing z to the left, all other terms to the right

z=150

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