5(2z-4)=9(z+3)

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Solution for 5(2z-4)=9(z+3) equation:


Simplifying
5(2z + -4) = 9(z + 3)

Reorder the terms:
5(-4 + 2z) = 9(z + 3)
(-4 * 5 + 2z * 5) = 9(z + 3)
(-20 + 10z) = 9(z + 3)

Reorder the terms:
-20 + 10z = 9(3 + z)
-20 + 10z = (3 * 9 + z * 9)
-20 + 10z = (27 + 9z)

Solving
-20 + 10z = 27 + 9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9z' to each side of the equation.
-20 + 10z + -9z = 27 + 9z + -9z

Combine like terms: 10z + -9z = 1z
-20 + 1z = 27 + 9z + -9z

Combine like terms: 9z + -9z = 0
-20 + 1z = 27 + 0
-20 + 1z = 27

Add '20' to each side of the equation.
-20 + 20 + 1z = 27 + 20

Combine like terms: -20 + 20 = 0
0 + 1z = 27 + 20
1z = 27 + 20

Combine like terms: 27 + 20 = 47
1z = 47

Divide each side by '1'.
z = 47

Simplifying
z = 47

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