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5(2z-6)=10(3-z)
We move all terms to the left:
5(2z-6)-(10(3-z))=0
We add all the numbers together, and all the variables
5(2z-6)-(10(-1z+3))=0
We multiply parentheses
10z-(10(-1z+3))-30=0
We calculate terms in parentheses: -(10(-1z+3)), so:We get rid of parentheses
10(-1z+3)
We multiply parentheses
-10z+30
Back to the equation:
-(-10z+30)
10z+10z-30-30=0
We add all the numbers together, and all the variables
20z-60=0
We move all terms containing z to the left, all other terms to the right
20z=60
z=60/20
z=3
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