5(2z-9)=9(z-5)+z

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Solution for 5(2z-9)=9(z-5)+z equation:


Simplifying
5(2z + -9) = 9(z + -5) + z

Reorder the terms:
5(-9 + 2z) = 9(z + -5) + z
(-9 * 5 + 2z * 5) = 9(z + -5) + z
(-45 + 10z) = 9(z + -5) + z

Reorder the terms:
-45 + 10z = 9(-5 + z) + z
-45 + 10z = (-5 * 9 + z * 9) + z
-45 + 10z = (-45 + 9z) + z

Combine like terms: 9z + z = 10z
-45 + 10z = -45 + 10z

Add '45' to each side of the equation.
-45 + 45 + 10z = -45 + 45 + 10z

Combine like terms: -45 + 45 = 0
0 + 10z = -45 + 45 + 10z
10z = -45 + 45 + 10z

Combine like terms: -45 + 45 = 0
10z = 0 + 10z
10z = 10z

Add '-10z' to each side of the equation.
10z + -10z = 10z + -10z

Combine like terms: 10z + -10z = 0
0 = 10z + -10z

Combine like terms: 10z + -10z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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