5(3+4x)=6X+29

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Solution for 5(3+4x)=6X+29 equation: 



5(3+4x)=6x+29

We move all terms to the left:

5(3+4x)-(6x+29)=0

We add all the numbers together, and all the variables

5(4x+3)-(6x+29)=0

We multiply parentheses

20x-(6x+29)+15=0

We get rid of parentheses

20x-6x-29+15=0

We add all the numbers together, and all the variables

14x-14=0

We move all terms containing x to the left, all other terms to the right

14x=14

x=14/14

x=1

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