5(3+5v)-5=29+6v

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Solution for 5(3+5v)-5=29+6v equation: 



5(3+5v)-5=29+6v

We move all terms to the left:

5(3+5v)-5-(29+6v)=0

We add all the numbers together, and all the variables

5(5v+3)-(6v+29)-5=0

We multiply parentheses

25v-(6v+29)+15-5=0

We get rid of parentheses

25v-6v-29+15-5=0

We add all the numbers together, and all the variables

19v-19=0

We move all terms containing v to the left, all other terms to the right

19v=19

v=19/19

v=1

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