5(3+c)=4(c-2)

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Solution for 5(3+c)=4(c-2) equation:


Simplifying
5(3 + c) = 4(c + -2)
(3 * 5 + c * 5) = 4(c + -2)
(15 + 5c) = 4(c + -2)

Reorder the terms:
15 + 5c = 4(-2 + c)
15 + 5c = (-2 * 4 + c * 4)
15 + 5c = (-8 + 4c)

Solving
15 + 5c = -8 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
15 + 5c + -4c = -8 + 4c + -4c

Combine like terms: 5c + -4c = 1c
15 + 1c = -8 + 4c + -4c

Combine like terms: 4c + -4c = 0
15 + 1c = -8 + 0
15 + 1c = -8

Add '-15' to each side of the equation.
15 + -15 + 1c = -8 + -15

Combine like terms: 15 + -15 = 0
0 + 1c = -8 + -15
1c = -8 + -15

Combine like terms: -8 + -15 = -23
1c = -23

Divide each side by '1'.
c = -23

Simplifying
c = -23

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