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5(3+x)=9(3-6x)
We move all terms to the left:
5(3+x)-(9(3-6x))=0
We add all the numbers together, and all the variables
5(x+3)-(9(-6x+3))=0
We multiply parentheses
5x-(9(-6x+3))+15=0
We calculate terms in parentheses: -(9(-6x+3)), so:We get rid of parentheses
9(-6x+3)
We multiply parentheses
-54x+27
Back to the equation:
-(-54x+27)
5x+54x-27+15=0
We add all the numbers together, and all the variables
59x-12=0
We move all terms containing x to the left, all other terms to the right
59x=12
x=12/59
x=12/59
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