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5(3-2x)+4(3x+1)=29
We move all terms to the left:
5(3-2x)+4(3x+1)-(29)=0
We add all the numbers together, and all the variables
5(-2x+3)+4(3x+1)-29=0
We multiply parentheses
-10x+12x+15+4-29=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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