5(3-2x)+4=3(4-x)

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Solution for 5(3-2x)+4=3(4-x) equation: 



5(3-2x)+4=3(4-x)

We move all terms to the left:

5(3-2x)+4-(3(4-x))=0

We add all the numbers together, and all the variables

5(-2x+3)-(3(-1x+4))+4=0

We multiply parentheses

-10x-(3(-1x+4))+15+4=0



We calculate terms in parentheses: -(3(-1x+4)), so:

3(-1x+4)

We multiply parentheses

-3x+12

Back to the equation:

-(-3x+12)



We add all the numbers together, and all the variables

-10x-(-3x+12)+19=0

We get rid of parentheses

-10x+3x-12+19=0

We add all the numbers together, and all the variables

-7x+7=0

We move all terms containing x to the left, all other terms to the right

-7x=-7

x=-7/-7

x=1

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