5(3-2x)-4(2-3x)=3-2(x+2)

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Solution for 5(3-2x)-4(2-3x)=3-2(x+2) equation: 



5(3-2x)-4(2-3x)=3-2(x+2)

We move all terms to the left:

5(3-2x)-4(2-3x)-(3-2(x+2))=0

We add all the numbers together, and all the variables

5(-2x+3)-4(-3x+2)-(3-2(x+2))=0

We multiply parentheses

-10x+12x-(3-2(x+2))+15-8=0



We calculate terms in parentheses: -(3-2(x+2)), so:

3-2(x+2)

determiningTheFunctionDomain
-2(x+2)+3

We multiply parentheses

-2x-4+3

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We add all the numbers together, and all the variables

2x-(-2x-1)+7=0

We get rid of parentheses

2x+2x+1+7=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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