5(3-2x)=10x+25-30

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Solution for 5(3-2x)=10x+25-30 equation:



5(3-2x)=10x+25-30
We move all terms to the left:
5(3-2x)-(10x+25-30)=0
We add all the numbers together, and all the variables
5(-2x+3)-(10x-5)=0
We multiply parentheses
-10x-(10x-5)+15=0
We get rid of parentheses
-10x-10x+5+15=0
We add all the numbers together, and all the variables
-20x+20=0
We move all terms containing x to the left, all other terms to the right
-20x=-20
x=-20/-20
x=1

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