5(3-2x)=3(4-x)

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Solution for 5(3-2x)=3(4-x) equation:



5(3-2x)=3(4-x)
We move all terms to the left:
5(3-2x)-(3(4-x))=0
We add all the numbers together, and all the variables
5(-2x+3)-(3(-1x+4))=0
We multiply parentheses
-10x-(3(-1x+4))+15=0
We calculate terms in parentheses: -(3(-1x+4)), so:
3(-1x+4)
We multiply parentheses
-3x+12
Back to the equation:
-(-3x+12)
We get rid of parentheses
-10x+3x-12+15=0
We add all the numbers together, and all the variables
-7x+3=0
We move all terms containing x to the left, all other terms to the right
-7x=-3
x=-3/-7
x=3/7

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