5(3-2x)=6(4-x)+10

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Solution for 5(3-2x)=6(4-x)+10 equation:



5(3-2x)=6(4-x)+10
We move all terms to the left:
5(3-2x)-(6(4-x)+10)=0
We add all the numbers together, and all the variables
5(-2x+3)-(6(-1x+4)+10)=0
We multiply parentheses
-10x-(6(-1x+4)+10)+15=0
We calculate terms in parentheses: -(6(-1x+4)+10), so:
6(-1x+4)+10
We multiply parentheses
-6x+24+10
We add all the numbers together, and all the variables
-6x+34
Back to the equation:
-(-6x+34)
We get rid of parentheses
-10x+6x-34+15=0
We add all the numbers together, and all the variables
-4x-19=0
We move all terms containing x to the left, all other terms to the right
-4x=19
x=19/-4
x=-4+3/4

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