5(3-2x)=7(4x-8)

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Solution for 5(3-2x)=7(4x-8) equation:



5(3-2x)=7(4x-8)
We move all terms to the left:
5(3-2x)-(7(4x-8))=0
We add all the numbers together, and all the variables
5(-2x+3)-(7(4x-8))=0
We multiply parentheses
-10x-(7(4x-8))+15=0
We calculate terms in parentheses: -(7(4x-8)), so:
7(4x-8)
We multiply parentheses
28x-56
Back to the equation:
-(28x-56)
We get rid of parentheses
-10x-28x+56+15=0
We add all the numbers together, and all the variables
-38x+71=0
We move all terms containing x to the left, all other terms to the right
-38x=-71
x=-71/-38
x=1+33/38

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