5(3-4x)=8(2x+1/4)

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Solution for 5(3-4x)=8(2x+1/4) equation: 



5(3-4x)=8(2x+1/4)

We move all terms to the left:

5(3-4x)-(8(2x+1/4))=0

We add all the numbers together, and all the variables

5(-4x+3)-(8(+2x+1/4))=0

We multiply parentheses

-20x-(8(+2x+1/4))+15=0

We multiply all the terms by the denominator


-20x*4))-(8(+2x+1+15*4))=0

We add all the numbers together, and all the variables

-20x*4))-(8(2x+61))=0

We add all the numbers together, and all the variables

-20x*4))-(8(2x=0

Wy multiply elements

-80x^2=0

a = -80; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-80)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-160}=0$

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