5(3-c)=c-12

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Solution for 5(3-c)=c-12 equation: 



5(3-c)=c-12

We move all terms to the left:

5(3-c)-(c-12)=0

We add all the numbers together, and all the variables

5(-1c+3)-(c-12)=0

We multiply parentheses

-5c-(c-12)+15=0

We get rid of parentheses

-5c-c+12+15=0

We add all the numbers together, and all the variables

-6c+27=0

We move all terms containing c to the left, all other terms to the right

-6c=-27

c=-27/-6

c=4+1/2

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