5(3-c/7)=8+1+2/3c

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Solution for 5(3-c/7)=8+1+2/3c equation: 


c in (-oo:+oo)

5*(3-(c/7)) = (2/3)*c+1+8 // - (2/3)*c+1+8

5*(3-(c/7))-((2/3)*c)-8-1 = 0

5*(3-(c/7))+(-2/3)*c-8-1 = 0

5*(3-1/7*c)+(-2*c)/3-8-1 = 0

(3*5*(3-1/7*c))/3+(-2*c)/3+(-8*3)/3+(-1*3)/3 = 0

3*5*(3-1/7*c)-2*c-8*3-1*3 = 0

45-29/7*c-24-3 = 0

21-29/7*c-3 = 0

18-29/7*c = 0

(18-29/7*c)/3 = 0

(18-29/7*c)/3 = 0 // * 3

18-29/7*c = 0

18-29/7*c = 0 // - 18

-29/7*c = -18 // : -29/7

c = -18/(-29/7)

c = 126/29

c = 126/29

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