5(3-h)=7+2(h+4)

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Solution for 5(3-h)=7+2(h+4) equation:



5(3-h)=7+2(h+4)
We move all terms to the left:
5(3-h)-(7+2(h+4))=0
We add all the numbers together, and all the variables
5(-1h+3)-(7+2(h+4))=0
We multiply parentheses
-5h-(7+2(h+4))+15=0
We calculate terms in parentheses: -(7+2(h+4)), so:
7+2(h+4)
determiningTheFunctionDomain 2(h+4)+7
We multiply parentheses
2h+8+7
We add all the numbers together, and all the variables
2h+15
Back to the equation:
-(2h+15)
We get rid of parentheses
-5h-2h-15+15=0
We add all the numbers together, and all the variables
-7h=0
h=0/-7
h=0

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