5(3-x)+1=4(x-2)-3

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Solution for 5(3-x)+1=4(x-2)-3 equation: 



5(3-x)+1=4(x-2)-3

We move all terms to the left:

5(3-x)+1-(4(x-2)-3)=0

We add all the numbers together, and all the variables

5(-1x+3)-(4(x-2)-3)+1=0

We multiply parentheses

-5x-(4(x-2)-3)+15+1=0



We calculate terms in parentheses: -(4(x-2)-3), so:

4(x-2)-3

We multiply parentheses

4x-8-3

We add all the numbers together, and all the variables

4x-11

Back to the equation:

-(4x-11)



We add all the numbers together, and all the variables

-5x-(4x-11)+16=0

We get rid of parentheses

-5x-4x+11+16=0

We add all the numbers together, and all the variables

-9x+27=0

We move all terms containing x to the left, all other terms to the right

-9x=-27

x=-27/-9

x=+3

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