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5(3-x)+8=3+2(x-4)
We move all terms to the left:
5(3-x)+8-(3+2(x-4))=0
We add all the numbers together, and all the variables
5(-1x+3)-(3+2(x-4))+8=0
We multiply parentheses
-5x-(3+2(x-4))+15+8=0
We calculate terms in parentheses: -(3+2(x-4)), so:We add all the numbers together, and all the variables
3+2(x-4)
determiningTheFunctionDomain 2(x-4)+3
We multiply parentheses
2x-8+3
We add all the numbers together, and all the variables
2x-5
Back to the equation:
-(2x-5)
-5x-(2x-5)+23=0
We get rid of parentheses
-5x-2x+5+23=0
We add all the numbers together, and all the variables
-7x+28=0
We move all terms containing x to the left, all other terms to the right
-7x=-28
x=-28/-7
x=+4
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