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5(3-x)-2(4-3x=11-2(x-+)
We move all terms to the left:
5(3-x)-2(4-3x-(11-2(x-+))=0
We add all the numbers together, and all the variables
5(-1x+3)-2(4-3x-(11-2(+x))=0
We multiply parentheses
-5x-2(4-3x-(11-2(+x))+15=0
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