5(3-x)=2(x-4)+15*

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Solution for 5(3-x)=2(x-4)+15* equation:



5(3-x)=2(x-4)+15*
We move all terms to the left:
5(3-x)-(2(x-4)+15*)=0
We add all the numbers together, and all the variables
5(-1x+3)-(2(x-4)+15*)=0
We multiply parentheses
-5x-(2(x-4)+15*)+15=0
We calculate terms in parentheses: -(2(x-4)+15*), so:
2(x-4)+15*
We add all the numbers together, and all the variables
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
We get rid of parentheses
-5x-2x+8+15=0
We add all the numbers together, and all the variables
-7x+23=0
We move all terms containing x to the left, all other terms to the right
-7x=-23
x=-23/-7
x=3+2/7

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