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5(3-x)=4(x+1)
We move all terms to the left:
5(3-x)-(4(x+1))=0
We add all the numbers together, and all the variables
5(-1x+3)-(4(x+1))=0
We multiply parentheses
-5x-(4(x+1))+15=0
We calculate terms in parentheses: -(4(x+1)), so:We get rid of parentheses
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
-5x-4x-4+15=0
We add all the numbers together, and all the variables
-9x+11=0
We move all terms containing x to the left, all other terms to the right
-9x=-11
x=-11/-9
x=1+2/9
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