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5(3/h)=15
We move all terms to the left:
5(3/h)-(15)=0
Domain of the equation: h)!=0We add all the numbers together, and all the variables
h!=0/1
h!=0
h∈R
5(+3/h)-15=0
We multiply parentheses
15h-15=0
We move all terms containing h to the left, all other terms to the right
15h=15
h=15/15
h=1
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