5(36-10)=-10b+50

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Solution for 5(36-10)=-10b+50 equation: 



5(36-10)=-10b+50

We move all terms to the left:

5(36-10)-(-10b+50)=0

We add all the numbers together, and all the variables

-(-10b+50)+526=0

We get rid of parentheses

10b-50+526=0

We add all the numbers together, and all the variables

10b+476=0

We move all terms containing b to the left, all other terms to the right

10b=-476

b=-476/10

b=-47+3/5

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