5(3a+4)+3(4a-5)=10

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Solution for 5(3a+4)+3(4a-5)=10 equation:


Simplifying
5(3a + 4) + 3(4a + -5) = 10

Reorder the terms:
5(4 + 3a) + 3(4a + -5) = 10
(4 * 5 + 3a * 5) + 3(4a + -5) = 10
(20 + 15a) + 3(4a + -5) = 10

Reorder the terms:
20 + 15a + 3(-5 + 4a) = 10
20 + 15a + (-5 * 3 + 4a * 3) = 10
20 + 15a + (-15 + 12a) = 10

Reorder the terms:
20 + -15 + 15a + 12a = 10

Combine like terms: 20 + -15 = 5
5 + 15a + 12a = 10

Combine like terms: 15a + 12a = 27a
5 + 27a = 10

Solving
5 + 27a = 10

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 27a = 10 + -5

Combine like terms: 5 + -5 = 0
0 + 27a = 10 + -5
27a = 10 + -5

Combine like terms: 10 + -5 = 5
27a = 5

Divide each side by '27'.
a = 0.1851851852

Simplifying
a = 0.1851851852

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