5(3a-2)+14a+6=9a-5(a+2)-14

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Solution for 5(3a-2)+14a+6=9a-5(a+2)-14 equation:



5(3a-2)+14a+6=9a-5(a+2)-14
We move all terms to the left:
5(3a-2)+14a+6-(9a-5(a+2)-14)=0
We add all the numbers together, and all the variables
14a+5(3a-2)-(9a-5(a+2)-14)+6=0
We multiply parentheses
14a+15a-(9a-5(a+2)-14)-10+6=0
We calculate terms in parentheses: -(9a-5(a+2)-14), so:
9a-5(a+2)-14
We multiply parentheses
9a-5a-10-14
We add all the numbers together, and all the variables
4a-24
Back to the equation:
-(4a-24)
We add all the numbers together, and all the variables
29a-(4a-24)-4=0
We get rid of parentheses
29a-4a+24-4=0
We add all the numbers together, and all the variables
25a+20=0
We move all terms containing a to the left, all other terms to the right
25a=-20
a=-20/25
a=-4/5

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