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5(3a-3)=2(4a+1)+60
We move all terms to the left:
5(3a-3)-(2(4a+1)+60)=0
We multiply parentheses
15a-(2(4a+1)+60)-15=0
We calculate terms in parentheses: -(2(4a+1)+60), so:We get rid of parentheses
2(4a+1)+60
We multiply parentheses
8a+2+60
We add all the numbers together, and all the variables
8a+62
Back to the equation:
-(8a+62)
15a-8a-62-15=0
We add all the numbers together, and all the variables
7a-77=0
We move all terms containing a to the left, all other terms to the right
7a=77
a=77/7
a=11
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